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stackoverflow

Password Encoder Match not working Spring boot

by Vermadeals February 16, 2023

written by Vermadeals

Answer –

passwordEncoder.matches(loginDTO.getEmail())

'matches(java.lang.CharSequence, java.lang.String)' in 'org.springframework.security.crypto.password.PasswordEncoder' cannot be applied to '(java.lang.String)'

Solution –

The error message you are seeing is indicating that the matches method of the PasswordEncoder interface expects two arguments: a CharSequence and a String. However, the code is passing a String as the first argument.

To fix this error, you can convert the String to a CharSequence before calling the matches method. You can do this using the CharSequence interface or by using a String as a CharSequence directly.

Here’s an example of how to fix the error using the CharSequence interface:

CharSequence password = loginDTO.getPassword();
String encodedPassword = user.getPassword(); // assume this is the encoded password from the database
if (passwordEncoder.matches(password, encodedPassword)) {
    // Passwords match
} else {
    // Passwords do not match
}

And here’s an example of how to fix the error by using a String as a CharSequence directly:

String password = loginDTO.getPassword();
String encodedPassword = user.getPassword(); // assume this is the encoded password from the database
if (passwordEncoder.matches(password, encodedPassword)) {
    // Passwords match
} else {
    // Passwords do not match
}

Either way, the important thing is to ensure that the first argument to the matches method is a CharSequence.

February 16, 2023 0 comment

Spring boot Stackoverflow

How to create custom filter in Spring Boot

by Vermadeals February 16, 2023

written by Vermadeals

Yes, in Spring Boot, you can add a custom filter to your web application using the @Component and @Order annotations.

Here’s an example of how you can create a custom filter:

1. Create a new class and annotate it with @Component to mark it as a Spring bean.

@Component
public class CustomFilter implements Filter {
    // Implement the methods of the Filter interface
}

2. Implement the methods of the javax.servlet.Filter interface in your custom filter class.

@Component
public class CustomFilter implements Filter {
    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
        // Initialization logic
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        // Filter logic
        chain.doFilter(request, response);
    }

    @Override
    public void destroy() {
        // Cleanup logic
    }
}

3. Use the @Order annotation to specify the order in which the filter should be applied. Lower numbers are processed first.

@Component
@Order(1)
public class CustomFilter implements Filter {
    // Implement the methods of the Filter interface
}

4. Spring Boot will automatically register your custom filter with the servlet container, and it will be applied to all incoming requests.

Note that you can also use the @WebFilter annotation instead of @Component to define a filter class. The @WebFilter annotation is a standard Java EE annotation, but it works in Spring Boot as well.

February 16, 2023 0 comment

Stackoverflow

Update old program to PHP8.1 I am updating an old reservation program as PHP?

by Vermadeals February 16, 2023

written by Vermadeals

Question-

I am updating an old reservation program as PHP? no longer supported. I have multiple select statements using output many times. Old code sample:

`$sql1 = "select route,fare,departure_time,from_location,arrival_time,to_location,notes,notice
FROM sectors2021
WHERE origin = '$origin'
AND destination = '$destination'
ORDER BY departure_time";
if ($result1 = mysql_query($sql1)) {
list ($route,$fare,$departure_time,$from_location,$arrival_time,$to_location,$notes,$notice) = 
mysql_fetch_array($result1);

} else {
$message .= '\<p\>\<center\>Could not select from Sectors!\</center\>\</p\>';
}`

Returns Error: Fatal error: Uncaught TypeError: mysqli_fetch_array(): Argument #1 ($result) must be of type mysqli_result, string given in /xxxx/xxxx/xxxx/xxxx/publicbook.php:217 Stack trace: #0 /xxxx/xxxx/xxxx/xxxx/publicbook.php(217): mysqli_fetch_array('select route,fa...') #1 {main} thrown in /xxxx/xxxx/xxxx/xxxx/publicbook.php on line 217

Solution –

There are a couple of issues with the code you provided. Here’s a corrected version:

$sql1 = "SELECT route, fare, departure_time, from_location, arrival_time, to_location, notes, notice
FROM sectors2021 
WHERE origin = '$origin' 
AND destination = '$destination'
ORDER BY departure_time";
// FETCHING DATA FROM DATABASE
$result1 = mysqli_query($conn, $sql1);
if (mysqli_num_rows($result1) > 0) {
  // OUTPUT DATA OF EACH ROW
  while ($row = mysqli_fetch_assoc($result1)) {
      $route = $row['route'];
      $fare = $row['fare'];
      $departure_time = $row['departure_time'];
      $from_location = $row['from_location'];
      $arrival_time = $row['arrival_time'];
      $to_location = $row['to_location'];
      $notes = $row['notes'];
      $notice = $row['notice'];
      
      echo "Route: $route";
  }
}

The main changes are:

Inside the while loop, you need to access the values from the $row variable that contains the current row’s data, instead of calling mysqli_fetch_array again with the SQL query.
Each column from the result set needs to be assigned to a separate variable for later use.
I added an echo statement to display the value of the $route variable, which is only available inside the while loop.

Note that you should also make sure to sanitize user input before using it in a SQL query to prevent SQL injection attacks.

February 16, 2023 0 comment